Haskell is—perhaps infamously—a lazy language. The basic idea of laziness is pretty easy to sum up in one sentence: values are only computed when they’re needed. But the implications of this are more subtle. In particular, it’s important to understand some crucial topics if you want to write memory- and time-efficient code:
seq
and deepseq
functions (and related concepts)This blog post was inspired by some questions around writing efficient conduit code, so I’ll try to address some of that directly at the end. The concepts, though, are general, and will transfer to not only other streaming libraries, but non-streaming data libraries too.
NOTE This blog post will mostly treat laziness as a problem to be solved, as opposed to the reality: laziness is sometimes an asset, and sometimes a liability. I’m focusing on the negative exclusively, because our goal here is to understand the rough edges and how to avoid them. There are many great things about laziness that I’m not even hinting at. I trust my readers to add some great links to articles speaking on the virtues of laziness in the comments 🙂
Let’s elaborate on my one liner above:
Values are only computed when they’re needed
Let’s explore this by comparison with a strict language: C.
#include <stdio.h>
int add(int x, int y) {
return x + y;
}
int main() {
int five = add(1 + 1, 1 + 2);
int seven = add(1 + 2, 1 + 3);
printf("Five: %dn", five);
return 0;
}
Our function add
is strict in both of its arguments. And its
result is also strict. This means that:
add
is called the first time, we will compute the result of
both 1 + 1
and 1 + 2
.add
function on 2
and 3
, get a result of 5
,
and place that value in memory pointed at by the variable five
.1 + 2
, 1 + 3
, and placing 7
in seven
.printf
with our five
value, which is already
fully computed.Let’s compare that to the equivalent Haskell code:
add :: Int -> Int -> Int
add x y = x + y
main :: IO ()
main = do
let five = add (1 + 1) (1 + 2)
seven = add (1 + 2) (1 + 3)
putStrLn $ "Five: " ++ show five
There’s something called strictness analysis which will result in something more efficient than what I’ll describe here in practice, but semantically, we’ll end up with the following:
1 + 1
and 1 + 2
, the compiler
will create a thunk (which you can think of as a promise) for
those computations, and pass those thunks to the add
function.add
function right away either: five
will be a thunk representing the application of the add
function
to the thunk for 1 + 1
and 1 + 2
.seven
: it will be a thunk
for applying add
to two other thunks.five
, we need to know
the actual number. This is called forcing evaluation. We’ll get
into more detail on when and how this happens below, but for now,
suffice it to say that when putStrLn
is executed, it forces
evaluation of five
, which forces evaluation of 1 + 1
and 1 + 2
, converting the thunks into real values (2
, 3
, and ultimately
5
).seven
is never used, it remains a thunk, and we don’t
spend time evaluating it.Compared to the C (strict) evaluation, there is one clear benefit: we
don’t bother wasting time evaluating the seven
value at all. That’s
three addition operations bypassed, woohoo! And in a real world
scenario, instead of being three additions, that could be a seriously
expensive operation.
However, it’s not all rosey. Creating a thunk does not come for
free: we need to allocate space for the thunk, which costs both
allocation, and causes GC pressure for freeing them
afterwards. Perhaps most importantly: the thunked version of an
expression can be far more costly than the evaluated version. Ignoring
some confusing overhead from data constructors (which only make the
problem worse), let’s compare our two representations of five
. In C,
five
takes up exactly one machine word*. In Haskell, our five
thunk will take up roughly:
* Or perhaps less, as int
is probably only 32 bits, and you’re
probably on a 64 bit machine. But then you get into alignment issues,
and registers… so let’s just say one machine word.
add
function, and the 1 + 1
and 1 + 2
thunks (one machine word each). So three machine words
total.1 + 1
thunk, one machine word for the thunk, and then
again a pointer to the +
operator, and the 1
values. (GHC has an
optimization where it will keep small int values in dedicated parts
of memory, avoiding extra overhead for the ints themselves. But you
could theoretically add in an extra machine word for each.) Again,
conservatively: three machine words.1 + 2
thunk, so three more machine words.Now in practice, it’s not going to work out that way. I mentioned the strictness analysis step, which will say “hey, wait a second, it’s totally better to just add two numbers than allocate a thunk, I’mma do that now, kthxbye.” But it’s vital when writing Haskell to understand all of these places where laziness and thunks can creep in.
Let’s look at how we can force Haskell to be more strict in its evaluation. Likely the easiest way to do this is with bang patterns. Let’s look at the code first:
{-# LANGUAGE BangPatterns #-}
add :: Int -> Int -> Int
add !x !y = x + y
main :: IO ()
main = do
let !five = add (1 + 1) (1 + 2)
!seven = add (1 + 2) (1 + 3)
putStrLn $ "Five: " ++ show five
This code now behaves exactly like the strict C code. Because we’ve
put a bang (!
) in front of the x
and y
in the add
function,
GHC knows that it must force evaluation of those values before
evaluating it. Similarly, by placing bangs on five
and seven
, GHC
must evaluate these immediately, before getting to putStrLn
.
As with many things in Haskell, however, bang patterns are just
syntactic sugar for something else. And in this case, that something
else is the seq
function. This function looks like:
seq :: a -> b -> b
You could implement this type signature yourself, of course, by just
ignoring the a
value:
badseq :: a -> b -> b
badseq a b = b
However, seq
uses primitive operations from GHC itself to ensure
that, when b
is evaluated, a
is evaluated too. Let’s rewrite our
add
function to use seq
instead of bang patterns:
add :: Int -> Int -> Int
add x y =
let part1 = seq x part2
part2 = seq y answer
answer = x + y
in part1
-- Or more idiomatically
add x y = x `seq` y `seq` x + y
What this is saying is this:
part1
is an expression which will tell you the value of part2
,
after it evaluates x
part2
is an expression which will tell you the value of answer
,
after it evaluates y
answer
is just x + y
Of course, that’s a long way to write this out, and the pattern is
common enough that people will usually just use seq
infix as
demonstrated above.
EXERCISE What would happen if, instead of in part1
, the code
said in part2
? How about in answer
?
There is always a straightforward translation from bang patterns to
usage of let
. We can do the same with the main
function:
main :: IO ()
main = do
let five = add (1 + 1) (1 + 2)
seven = add (1 + 2) (1 + 3)
five `seq` seven `seq` putStrLn ("Five: " ++ show five)
It’s vital to understand how seq
is working, but there’s no
advantage to using it over bang patterns where the latter are clear
and easy to read. Choose whichever option makes the code easiest to
read, which will often be bang patterns.
So far, you’ve just had to trust me about the evaluation of thunks
occurring. Let’s see a method to more directly observe evaluation. The
trace
function from Debug.Trace
will print a message when it is
evaluated. Take a guess at the output of these programs:
#!/usr/bin/env stack
-- stack --resolver lts-12.21 script
import Debug.Trace
add :: Int -> Int -> Int
add x y = x + y
main :: IO ()
main = do
let five = trace "five" (add (1 + 1) (1 + 2))
seven = trace "seven" (add (1 + 2) (1 + 3))
putStrLn $ "Five: " ++ show five
Versus:
#!/usr/bin/env stack
-- stack --resolver lts-12.21 script
{-# LANGUAGE BangPatterns #-}
import Debug.Trace
add :: Int -> Int -> Int
add x y = x + y
main :: IO ()
main = do
let !five = trace "five" (add (1 + 1) (1 + 2))
!seven = trace "seven" (add (1 + 2) (1 + 3))
putStrLn $ "Five: " ++ show five
Think about this before looking at the answer…
OK, hope you had a good think. Here’s the answer:
five
and Five: 5
. It will not
bother printing seven
, since that expression is never forced. (Due
to strangeness around output buffering, you may see interleaving of
these two output values.)five
and seven
, because the bang
patterns force their evaluation. However, the order of their
output may be different than you expect. On my system, for example,
seven
prints before five
. That’s because GHC retains the right
to rearrange order of evaluation in these cases.five `seq` seven `seq` putStrLn ("Five: " ++ show five)
, it comes out in the order you would intuitively
expect: first five, then seven, and then “Five: 5”. This gives a
bit of a lie to my claim that bang patterns are always a simple
translation to seq
s. However, the fact is that with an expression
x `seq` y
, GHC is free to choose whether it evaluates x
or y
first, as long as it ensure that when that expression finishes
evaluating, both x
and y
are evaluated.All that said: as long as your expressions are truly pure, you will be
unable to observe the difference between x
and y
evaluating
first. Only the fact that we used trace
, which is an impure
function, allowed us to observe the order of evaluation.
QUESTION Does the result change at all if you put bangs on the
add
function? Why do bangs there affect (or not affect) the output?
This is all well and good, but the more standard way to demonstrate
evaluation order is to use bottom values, aka undefined
. undefined
is special in that, when it is evaluated, it throws a runtime
exception. (The error
function does the same thing, as do a few
other special functions and values.) To demonstrate the same thing
about seven
not being evaluated without the bangs, compare these two
programs:
#!/usr/bin/env stack
-- stack --resolver lts-12.21 script
{-# LANGUAGE BangPatterns #-}
add :: Int -> Int -> Int
add x y = x + y
main :: IO ()
main = do
let five = add (1 + 1) (1 + 2)
seven = add (1 + 2) undefined -- (1 + 3)
putStrLn $ "Five: " ++ show five
Versus:
#!/usr/bin/env stack
-- stack --resolver lts-12.21 script
{-# LANGUAGE BangPatterns #-}
add :: Int -> Int -> Int
add x y = x + y
main :: IO ()
main = do
let five = add (1 + 1) (1 + 2)
!seven = add (1 + 2) undefined -- (1 + 3)
putStrLn $ "Five: " ++ show five
The former completes without issue, since seven
is never
evaluated. However, in the latter, we have a bang pattern on
seven
. What GHC does here is:
add (1 + 2) undefined
(1 + 2) + undefined
+
operator, it needs actual values for
the two arguments, not just thunks. This can be seen as if +
has
bang patterns on its arguments. The correct way to say this is “+
is strict in both of its arguments.”1 + 2
or undefined
first. Let’s assume it does 1 + 2
first. It will come up with two
evaluated values (1
and 2
), pass them to +
, and get back
3
. All good.undefined
, which triggers a
runtime exception to be thrown.QUESTION Returning to the question above: does it look like bang
patterns inside the add
function actually accomplish anything? Think
about what the output of this program will be:
#!/usr/bin/env stack
-- stack --resolver lts-12.21 script
{-# LANGUAGE BangPatterns #-}
add :: Int -> Int -> Int
add !x !y = x + y
main :: IO ()
main = do
let five = add (1 + 1) (1 + 2)
seven = add (1 + 2) undefined -- (1 + 3)
putStrLn $ "Five: " ++ show five
To compare this behavior to a strict language, we need a language with something like runtime exceptions. I’ll use Rust’s panics:
fn add(x: isize, y: isize) -> isize {
println!("adding: {} and {}", x, y);
x + y
}
fn main() {
let five = add(1 + 1, 1 + 2);
let seven = add(1 + 2, panic!());
println!("Five: {}", five);
}
Firstly, to Rust’s credit: it gives me a bunch of warnings about how
this program is dumb. Fair enough, but I’m going to ignore those
warnings and charge ahead with it. This program will first evaluate
the add(1 + 1, 1 + 2)
expression (which we can see in the output of
adding: 2 and 3
). Then, before it ever enters the add
function the
second time, it needs to evaluate both 1 + 2
and panic!()
. The
former works just fine, but the latter results in a panic being
generated and short-circuiting the rest of our function.
If we want to regain Haskell’s laziness properties, there’s a
straightforward way to do it: use a closure. A closure is,
essentially, a thunk. The Rust syntax for creating a closure is
|args| body
. We can create closures with no arguments to act like
thunks, which gives us:
fn add<X, Y>(x: X, y: Y) -> isize
where X: FnOnce() -> isize,
Y: FnOnce() -> isize {
let x = x();
let y = y();
println!("adding: {} and {}", x, y);
x + y
}
fn main() {
let five = || add(|| 1 + 1, || 1 + 2);
let seven = || add(|| 1 + 2, || panic!());
println!("Five: {}", five());
}
Again, the Rust compiler complains about the unused seven
, but this
program succeeds in running, since we never run the seven
closure.
Still not up to speed with Rust? Let’s use everyone’s favorite language: Javascript:
function add(x, y) {
return x() + y();
}
function panic() {
throw "Panic!"
}
var five = ignored => add(ignored => 1 + 1, ignored => 1 + 2);
var seven = ignored => add(ignored => 1 + 2, panic);
console.log("Five: " + five());
Alright, to summarize until now:
seq
to make things strictundefined
) and seeing if it explodes in your facetrace
function can help you see this as wellThis is all good, and make sure you have a solid grasp of these concepts before continuing. Consider rereading the sections above.
Here’s something we didn’t address: what, exactly, does it mean to
evaluate or force a value? To demonstrate the problem, let’s implement
an average function. We’ll use a helper datatype, called
RunningTotal
, to capture both the cumulative sum and the number of
elements we’ve seen so far.
data RunningTotal = RunningTotal
{ sum :: Int
, count :: Int
}
printAverage :: RunningTotal -> IO ()
printAverage (RunningTotal sum count)
| count == 0 = error "Need at least one value!"
| otherwise = print (fromIntegral sum / fromIntegral count :: Double)
-- | A fold would be nicer... we'll see that later
printListAverage :: [Int] -> IO ()
printListAverage =
go (RunningTotal 0 0)
where
go rt [] = printAverage rt
go (RunningTotal sum count) (x:xs) =
let rt = RunningTotal (sum + x) (count + 1)
in go rt xs
main :: IO ()
main = printListAverage [1..1000000]
We’re going to run this with run time statistics turned on so we can look at memory usage:
$ stack ghc average.hs && ./average +RTS -s
Lo and behold, our memory usage is through the roof!
[1 of 1] Compiling Main ( average.hs, average.o )
Linking average ...
500000.5
258,654,528 bytes allocated in the heap
339,889,944 bytes copied during GC
95,096,512 bytes maximum residency (9 sample(s))
1,148,312 bytes maximum slop
164 MB total memory in use (0 MB lost due to fragmentation)
We’re allocating a total of 258MB, and keeping 95MB in memory at once. For something that should just be a tight inner loop, that’s ridiculously large.
You’re probably thinking right now “shouldn’t we use that seq
stuff
or those bang patterns?” Certainly that makes sense. And in fact, it
looks really trivial to solve this problem with a single bang to force
evaluation of the newly constructed rt
before recursing back into
go
. For example, we can add {-# LANGUAGE BangPatterns #-}
to the
top of our file and then define go
as:
go !rt [] = printAverage rt
go (RunningTotal sum count) (x:xs) =
let rt = RunningTotal (sum + x) (count + 1)
in go rt xs
Unfortunately, this results in exactly the same memory usage as we had before. In order to understand why this is happening, we need to look at something called weak head normal form.
Note in advance that there’s a great Stack Overflow answer on this topic for further reading.
We’ve been talking about forcing values and evaluating expressions, but what exactly that means hasn’t been totally clear. To start simple, what will the output of this program be?
main = putStrLn $ undefined `seq` "Hello World"
You’d probably guess that it will print an error about undefined
,
since it will try to evaluate undefined
before it will evaluate
"Hello World"
, and because putStrLn
is strict in its argument. And
you’d be correct. But let’s try something a little bit different:
main = putStrLn $ Just undefined `seq` "Hello World"
If you assume that “evaluate” means “fully evaluate into something
with no thunks left,” you’ll say that this, too, prints an undefined
error. But in fact, it happily prints out “Hello World” with no
exceptions. What gives?
It turns out that when we talk about forcing evaluation with seq
,
we’re only talking about evaluating to weak head normal form
(WHNF). For most data types, this means unwrapping one layer of
constructor. In the case of Just undefined
, it means that we unwrap
the Just
data constructor, but don’t touch the undefined
within
it. (We’ll see a few ways to deal with this differently below.)
It turns out that, with a standard data constructor*, the impact of
using seq
is the same as pattern matching the outermost
constructor. If you want to monomorphise, for example, you can
implement a function of type seqMaybe :: Maybe a -> b -> b
and use
it in the main
example above. Go ahead and give it a shot… answer
below.
* Hold your horses, we’ll talk about newtype
s later and then you’ll
understand this weird phrasing.
seqMaybe :: Maybe a -> b -> b
seqMaybe Nothing b = b
seqMaybe (Just _) b = b
main :: IO ()
main = do
putStrLn $ Just undefined `seqMaybe` "Hello World"
putStrLn $ undefined `seqMaybe` "Goodbye!"
Let’s up the ante again. What do you think this program will print?
main = do
putStrLn $ error `seq` "Hello"
putStrLn $ (x -> undefined) `seq` "World"
putStrLn $ error "foo" `seq` "Goodbye!"
You might think that error `seq` ...
would be a problem. After
all, isn’t error
going to throw an exception? However, error
is a
function. There’s no exception getting thrown, or no bottom value
being provided, until error
is given its String
argument. As a
result, evaluating does not, in fact, generate an error. The rule is:
any function applied to too few values is automatically in WHNF.
A similar logic applies to (x -> undefined)
. Although it’s a lambda
expression, its type is a function which has not been applied to all
arguments. And therefore, it will not throw an exception when
evaluated. In other words, it’s already in WHNF.
However, error "foo"
is a function fully applied to its
arguments. It’s no longer a function, it’s a value. And when we try to
evaluate it to WHNF, its exception blows up in our face.
EXERCISE Will the following throw exceptions when evaluated?
(+) undefined
Just undefined
undefined 5
(error "foo" :: Int -> Double)
Having understood WHNF, let’s return to our example and see why our first bang pattern did nothing to help us:
go !rt [] = printAverage rt
go (RunningTotal sum count) (x:xs) =
let rt = RunningTotal (sum + x) (count + 1)
in go rt xs
In WHNF, forcing evaluation is the same as unwrapping the constructor,
which we are already doing in the second clause! The problem is that
the values contained inside the RunningTotal
data constructor are
not being evaluated, and therefore are accumulating thunks. Let’s see
two ways to solve this:
go rt [] = printAverage rt
go (RunningTotal !sum !count) (x:xs) =
let rt = RunningTotal (sum + x) (count + 1)
in go rt xs
Instead of putting the bangs on the RunningTotal
value, I’m putting
them on the values within the constructor, forcing them to be
evaluated at each loop. We’re no longer accumulating a huge chain of
thunks, and our maximum residency drops to 44kb. (Total allocations,
though, are still up around 192mb. We need to play around with other
optimizations outside the scope of this post to deal with the total
allocations, so we’re going to ignore this value for the rest of the
examples.) Another approach is:
go rt [] = printAverage rt
go (RunningTotal sum count) (x:xs) =
let !sum' = sum + x
!count' = count + 1
rt = RunningTotal sum' count'
in go rt xs
This one instead forces evaluation of the new sum and count before
constructing the new RunningTotal
value. I like this version a bit
more, as it’s forcing evaluation at the correct point: when creating
the value, instead of on the next iteration of the loop when
destructing it.
Moral of the story: make sure you’re evaluating the thing you actually need to evaluate, not just its container!
The fact that seq
only evaluates to weak head normal form is
annoying. There are lots of times when we would like to fully evaluate
down to normal form (NF), meaning all thunks have been evaluated
inside our values. While there is nothing built into the language to
handle this, there is a semi-standard (meaning it ships with GHC)
library to handle this: deepseq
. It works by providing an NFData
type class the defines how to reduce a value to normal form (via the
rnf
method).
{-# LANGUAGE BangPatterns #-}
import Control.DeepSeq
data RunningTotal = RunningTotal
{ sum :: Int
, count :: Int
}
instance NFData RunningTotal where
rnf (RunningTotal sum count) = sum `deepseq` count `deepseq` ()
printAverage :: RunningTotal -> IO ()
printAverage (RunningTotal sum count)
| count == 0 = error "Need at least one value!"
| otherwise = print (fromIntegral sum / fromIntegral count :: Double)
-- | A fold would be nicer... we'll see that later
printListAverage :: [Int] -> IO ()
printListAverage =
go (RunningTotal 0 0)
where
go rt [] = printAverage rt
go (RunningTotal sum count) (x:xs) =
let rt = RunningTotal (sum + x) (count + 1)
in rt `deepseq` go rt xs
main :: IO ()
main = printListAverage [1..1000000]
This has a maximum residency, once again, of 44kb. We define our
NFData
instance, which includes an rnf
method. The approach of
simply deepseq
ing all of the values within a data constructor is
almost always the approach to take for NFData
instances. In fact,
it’s so common, that you can get away with just using Generic
deriving and have GHC do the work for you:
{-# LANGUAGE DeriveGeneric #-}
import GHC.Generics (Generic)
import Control.DeepSeq
data RunningTotal = RunningTotal
{ sum :: Int
, count :: Int
}
deriving Generic
instance NFData RunningTotal
The true beauty of having NFData
instances is the ability to
abstract over many different data types. We can use this not only to
avoid space leaks (as we’re doing here), but also to avoid
accidentally including exceptions inside thunks within a value. For an
example of that, check out the
tryAnyDeep
function from the
safe-exceptions library.
EXERCISE Define the deepseq
function yourself in terms of rnf
and seq
.
These approaches work, but they are not ideal. The problem lies in our
definition of RunningTotal
. What we want to say is that, whenever
you have a value of type RunningTotal
, you in fact have two
Int
s. But because of laziness, what we’re actually saying is that a
RunningTotal
value could contain two Int
s, or it could contain
thunks that will evaluate to Int
s, or thunks that will throw
exceptions.
Instead, we’d like to make it impossible to construct a RunningTotal
value that has any laziness room left over. And to do that, we can use
strictness annotations in our definition of the data type:
data RunningTotal = RunningTotal
{ sum :: !Int
, count :: !Int
}
deriving Generic
printAverage :: RunningTotal -> IO ()
printAverage (RunningTotal sum count)
| count == 0 = error "Need at least one value!"
| otherwise = print (fromIntegral sum / fromIntegral count :: Double)
-- | A fold would be nicer... we'll see that later
printListAverage :: [Int] -> IO ()
printListAverage =
go (RunningTotal 0 0)
where
go rt [] = printAverage rt
go (RunningTotal sum count) (x:xs) =
let rt = RunningTotal (sum + x) (count + 1)
in go rt xs
main :: IO ()
main = printListAverage [1..1000000]
All we’ve done is put bangs in front of the Int
s in the definition
of RunningTotal
. We have no other references to strictness or
evaluation in our program. However, by placing the strictness
annotations on those fields, we’re saying something simple and yet
profound:
Whenever you evaluate a value of type RunningTotal
, you must also
evaluate the two Int
s it contains
As we mentioned above, our second go
clause forces evaluation of the
RunningTotal
value by taking apart its constructor. This act now
automatically forces evaluation of sum
and count
, which we
previously needed to achieve via a bang pattern.
There’s one other advantage to this, which is slightly out of scope
but worth mentioning. When dealing with small values like an Int
,
GHC will automatically unbox strict fields. This means that, instead
of keeping a pointer to an Int
inside RunningTotal
, it will keep
the Int
itself. This can further reduce memory usage.
You’re probably asking a pretty good question right now: “how do I know if I should use a strictness annotation on my data fields?” This answer is slightly controversial, but my advice and recommended best practice: unless you know that you want laziness for a field, make it strict. Making your fields strict helps in a few ways:
Let’s define three very similar data types:
data Foo = Foo Int
data Bar = Bar !Int
newtype Baz = Baz Int
Let’s play a game, and guess the output of the following potential
bodies for main
. Try to work through each case in your head before
reading the explanation below.
case undefined of { Foo _ -> putStrLn "Still alive!" }
case Foo undefined of { Foo _ -> putStrLn "Still alive!" }
case undefined of { Bar _ -> putStrLn "Still alive!" }
case Bar undefined of { Bar _ -> putStrLn "Still alive!" }
case undefined of { Baz _ -> putStrLn "Still alive!" }
case Baz undefined of { Baz _ -> putStrLn "Still alive!" }
Case (1) is relatively straightforward: we try to unwrap one layer of
data constructor (the Foo
) and find a bottom value. So this thing
throws an exception. The same thing applies to (3).
(2) does not throw an exception. We have a Foo
data constructor in
our expression, and it contains a bottom value. However, since there
is no strictness annotation on the Int
in Foo
, uwnrapping the
Foo
does not force evaluation of the Int
, and therefore no
exception is thrown. By contrast, in (4), we do have a strictness
annotation, and therefore case
ing on Bar
throws an exception.
What about newtype
s? What we know about newtype
s is that they have
no runtime representation. Therefore, it’s impossible for the Baz
data constructor to be hiding an extra layer of bottomness. In other
words, Baz undefined
and undefined
are indistinguishable. That may
sound like Bar
at first, but interestingly it’s not.
You see, unwrapping a Baz
constructor can have no effect on runtime
behavior, since it was never there in the first place. The pattern
match inside (5), therefore, does nothing. It is equivalent to case undefined of { _ -> putStrLn "Still alive!" }
. And since we’re not
inspecting the undefined
at all (because we’re using a wildcard
pattern and not a data constructor), no exception is thrown.
Similarly, in case (6), we’ve applied a Baz
constructor to
undefined
, but since it has no runtime representation, it may as
well not be there. So once again, no exception is thrown.
EXERCISE What is the output of the program main = Baz undefined `seq` putStrLn "Still alive!"
? Why?
It can be inconvenient, as you may have noticed already, to use seq
and deepseq
all over the place. Bang patterns help, but there are
other ways to force evaluation. Perhaps the most common is the $!
operator, e.g.:
mysum :: [Int] -> Int
mysum list0 =
go list0 0
where
go [] total = total
go (x:xs) total = go xs $! total + x
main = print $ mysum [1..1000000]
This forces evaluation of total + x
before recursing back into the
go
function, avoiding a space leak. (EXERCISE: do the same thing
with a bang pattern, and with the seq
function.)
The $!!
operator is the same, except instead of working with seq
,
it uses deepseq
and therefore evaluates to normal form.
import Control.DeepSeq
average :: [Int] -> Double
average list0 =
go list0 (0, 0)
where
go [] (total, count) = fromIntegral total / count
go (x:xs) (total, count) = go xs $!! (total + x, count + 1)
main = print $ average [1..1000000]
Another nice helper function is
force
. What
this does is makes it that, when the expression you’re looking at is
evaluated to WHNF, it’s actually evaluated to NF. For example, we
can rewrite the go
function above as:
go [] (total, count) = fromIntegral total / count
go (x:xs) (total, count) = go xs $! force (total + x, count + 1)
EXERCISE Define these convenience functions and operators yourself
in terms of seq
and deepseq
.
Alright, I swear that’s all of the really complicated stuff. If you’ve absorbed all of those details, the rest of this just follows naturally and introduces a little bit more terminology to help us understand things.
Let’s start off slowly: what’s the output of this program:
data List a = Cons a (List a) | Nil
main = Cons undefined undefined `seq` putStrLn "Hello World"
Well, using our principles from above: Cons undefined undefined
is
already in WHNF, since we’ve got the outermost constructor
available. So this program prints “Hello World”, without any
exceptions. Cool. Now let’s realize that Cons
is the same as the :
data constructor for lists, and see that the above is identical to:
main = (undefined:undefined) `seq` putStrLn "Hello World"
This tells me that lists are a lazy data structure: I have a bottom value for the first element, a bottom value for the rest of the list, and yet this first cell is not bottom. Let’s try something a little bit different:
data List a = Cons a !(List a) | Nil
main = Cons undefined undefined `seq` putStrLn "Hello World"
This is going to explode in our faces! We are now strict in the tail of the list. However, the following is fine:
data List a = Cons a !(List a) | Nil
main = Cons undefined (Cons undefined Nil) `seq` putStrLn "Hello World"
With this definition of a list, we need to know all the details about the list itself, but the values can remain undefined. This is called spine strict. By contrast, we can also be strict in the values and be value strict:
data List a = Cons !a !(List a) | Nil
main = Cons undefined (Cons undefined Nil) `seq` putStrLn "Hello World"
This will explode in our faces, as we’d expect.
There’s one final definition of list you may be expecting, one strict in values but not in the tail:
data List a = Cons !a (List a) | Nil
In practice, I’m aware of no data structures in Haskell that follow this pattern, and therefore it doesn’t have a name. (If there are such data structures, and this does have a name, please let me know, I’d be curious about the use cases for it.)
So standard lists are lazy. Let’s look at a few other data types:
The vectors in Data.Vector
(also known as boxed vectors) are spine
strict. Assuming an import of import qualified Data.Vector as V
,
what would be the results of the following programs?
main = V.fromList [undefined] `seq` putStrLn "Hello World"
main = V.fromList (undefined:undefined) `seq` putStrLn "Hello World"
main = V.fromList undefined `seq` putStrLn "Hello World"
The first succeeds: we have the full spine of the vector defined. The fact that it contains a bottom value is irrelevant. The second fails, since the spine of the tail of the list is undefined, making the spine undefined. And finally the third (of course) fails, since the entire list is undefined.
Now let’s look at unboxed vectors. Because of inference issues, we need to help out GHC a little bit more. So starting with this head of a program:
import qualified Data.Vector.Unboxed as V
fromList :: [Int] -> V.Vector Int
fromList = V.fromList
What happens with the three cases above?
main = fromList [undefined] `seq` putStrLn "Hello World"
main = fromList (undefined:undefined) `seq` putStrLn "Hello World"
main = fromList undefined `seq` putStrLn "Hello World"
As you’d expect, (2) and (3) have the same behavior as with boxed vectors. However, (1) also throws an exception, since unboxed vectors are value strict, not just spine strict. The same applies to storable and primitive vectors.
Unfortunately, to my knowledge, there is no definition of a strict, boxed vector in a public library. Such a data type would be useful to help avoid space leaks (such as the original question that triggered this blog post).
If you look at the containers and unordered-containers packages, you
may have noticed that the Map-like modules come in Strict
and Lazy
variants (e.g., Data.HashMap.Strict
and Data.HashMap.Lazy
) while
the Set-like modules do not (e.g., Data.IntSet
). This is because
all of these containers are spine strict, and therefore must be
strict in the keys. Since a set only has keys, no separate values, it
must also be value strict.
A map, by contrast, has both keys and values. The lazy variants of the map-like modules are spine-strict, value-lazy, whereas the strict variants are both spine and value strict.
EXERCISE Analyze the Data.Sequence.Seq
data type and classify it
as either lazy, spine strict, or value strict.
A function is considered strict in one of its arguments if, when the
function is applied to a bottom value for that argument, the result is
bottom. As we saw way above, +
for Int
is strict in both of its
arguments, since: undefined + x
is bottom, and x + undefined
is
bottom.
By contrast, the const
function, defined as const a b = a
, is
strict in its first argument and lazy in its second argument.
The :
data constructor for lists is lazy in both its first and
second argument. But if you have data List = Cons !a !(List a) | Nil
, Cons
is strict in both its first and second argument.
A common place to end up getting tripped up by laziness is dealing
with folds. The most infamous example is the foldl
function, which
lulls you into a false sense of safety only to dash your hopes and
destroy your dreams:
mysum :: [Int] -> Int
mysum = foldl (+) 0
main :: IO ()
main = print $ mysum [1..1000000]
This is so close to correct, and yet uses 53mb of resident memory! The
solution is but a tick away, using the strict left fold foldl'
function:
import Data.List (foldl')
mysum :: [Int] -> Int
mysum = foldl' (+) 0
main :: IO ()
main = print $ mysum [1..1000000]
Why does the Prelude
expose a function (foldl
) which is almost
always the wrong one to use?
But the important thing to note about almost all functions that claim
to be strict is that they are only strict to weak head normal
form. Pulling up our average
example from before, this still has a
space leak:
import Data.List (foldl')
average :: [Int] -> Double
average =
divide . foldl' add (0, 0)
where
divide (total, count) = fromIntegral total / count
add (total, count) x = (total + x, count + 1)
main :: IO ()
main = print $ average [1..1000000]
My advice is to use a helper data type with strict fields. But perhaps
you don’t want to do that, and you’re frustrated that there is no
foldl'
that evaluates to normal form. Fortunately for you, by just
throwing in a call to force
, you can easily upgrade a WHNF fold into
a NF fold:
import Data.List (foldl')
import Control.DeepSeq (force)
average :: [Int] -> Double
average =
divide . foldl' add (0, 0)
where
divide (total, count) = fromIntegral total / count
add (total, count) x = force (total + x, count + 1)
main :: IO ()
main = print $ average [1..1000000]
Like a good plumber, force
patches that leak right up!
One of the claims of streaming data libraries (like conduit) is that they promote constant memory usage. This may make you think that you can get away without worrying about space leaks. However, all of the comments about WHNF vs NF mentioned above apply. To prove the point, let’s do average badly with conduit:
import Conduit
average :: Monad m => ConduitM Int o m Double
average =
divide <$> foldlC add (0, 0)
where
divide (total, count) = fromIntegral total / count
add (total, count) x = (total + x, count + 1)
main :: IO ()
main = print $ runConduitPure $ enumFromToC 1 1000000 .| average
You can test the memory usage of this with:
$ stack --resolver lts-12.21 ghc --package conduit-combinators -- Main.hs -O2
$ ./Main +RTS -s
EXERCISE Make this program run in constant resident memory, by using:
force
functionLook at this super strict program. It’s got a special value-strict
list data type. I’ve liberally sprinkled bang patterns and calls to
seq
throughout. I’ve used $!
. How much memory do you think it
uses?
#!/usr/bin/env stack
-- stack --resolver lts-12.21 script
{-# LANGUAGE BangPatterns #-}
data StrictList a = Cons !a !(StrictList a) | Nil
strictMap :: (a -> b) -> StrictList a -> StrictList b
strictMap _ Nil = Nil
strictMap f (Cons a list) =
let !b = f a
!list' = strictMap f list
in b `seq` list' `seq` Cons b list'
strictEnum :: Int -> Int -> StrictList Int
strictEnum low high =
go low
where
go !x
| x == high = Cons x Nil
| otherwise = Cons x (go $! x + 1)
double :: Int -> Int
double !x = x * 2
evens :: StrictList Int
evens = strictMap double $! strictEnum 1 1000000
main :: IO ()
main = do
let string = "Hello World"
string' = evens `seq` string
putStrLn string
Look carefully, read the code well, and make a guess. Ready? Good.
It uses 44kb of memory. “What?!” you may exclaim. “But this thing has
to hold onto a million Int
s in a strict linked list!”
Ehh… almost. It’s true, our program is going to do a hell of a lot
of evaluation as soon as we force the evens
value. And as soon as we
force the string'
value in main
, we’ll force evens
.
However, our program never actually forces evaluation of either of
these! If you look carefully, the last line in the program uses the
string
value. It never looks at string'
or evens
. When executing
our program, GHC is only interested in performing the IO
actions it
is told to perform by the main
function. And main
only says
something about putStrLn string
.
This is vital to understand. You can build up as many chains of
evaluation using seq
and deepseq
as you want in your program. But
ultimately, unless you force evaluation via some IO
action of the
value at the top of the chain, it will all remain an unevaluated
thunk.
EXERCISES
putStrLn string
to putStrLn string'
and see what happens
to memory usage. (Then undo that change for the other exercises.)main
somewhere to get the great memory
usage.seq
somewhere in the putStrLn string
line to force the
greater memory usage.
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